For the first part, since the solenoid is long we can approximate the magnetic field inside to be uniform and is given by Bz=μ0NI, so we can say that the magnetic field at the center is also μ0NI.
What is the magnetic field at the end of solenoid?
The magnetic field at the ends of a very long current carrying solenoid is half of that at the centre.
How do you find the magnetic field at the center of a solenoid?
Ans: The magnetic field due to the solenoid formula is as follows, B = μ₀ (NI/l) or B = μ₀nI. In both cases the number of turns is directly proportional to the magnetic field, thus by increasing or by doubling the number of turns it directly affects the magnetic field and it increases.
Where the magnetic field of a solenoid is strongest?
The magnetic field is strongest inside the coil of a solenoid.
How do you find the magnetic flux through a solenoid?
No, the book is correct, the magnetic flux (the amount of magnetism) going through the solenoid is the magnetic field strength B multiplied by the area of the solenoid A=πR2. The magnetic flux linkage is the amount of magnetism multiplied by the number of turns of the coil.
Why is there no magnetic field outside a solenoid?
Magnetic field lines only exist as loops, they cannot diverge from or converge to a point like electric field lines can (see Gauss’s law for magnetism). … However, the volume outside the solenoid is much greater than the volume inside, so the density of magnetic field lines outside is greatly reduced.
Why magnetic field is half at the end of the solenoid?
It becomes half because the magnetic field strength on the axis going right through the solenoid, in the place on the end of the solenoid is then the field of an infinitely long solenoid minus half of it because half is missing, and so the field strength is half as big on the ends (but right in the middle).
How do you calculate the magnetic field outside a solenoid?
Therefore, the magnetic field inside and near the middle of the solenoid is given by Equation 12.7. 11. Outside the solenoid, the magnetic field is zero. n=300turns0.140m=2.14×103turns/m.
Why is the magnetic field inside a solenoid stronger?
When a direct electric current is passed through it, the shape of the magnetic field is very similar to the field of a bar magnet. The field inside a solenoid is strong and uniform. The small magnetic fields caused by the current in each turn of the coil add together to make a stronger overall magnetic field.
What happens if we change the magnetic field around a solenoid?
If a magnet is moved inside the solenoid, the flux changes, which induces a current in the solenoid.
Is magnetic flux solenoid?
solenoid: A coil of wire that acts as a magnet when an electric current flows through it. flux: The rate of transfer of energy (or another physical quantity) through a given surface, specifically electric flux or magnetic flux.
How do you calculate the force of a solenoid?
The force is F=A *B^2/2*mu_knot. For a traditional solenoid, a common expression for magnetic field is: B=Bsol=mu_knot*N*I/g, where g = gap. Then, F=mu_knot*A*(NI/g)^2/2 [same as your equation, without NdFeB.]
How do you calculate the number of turns on a solenoid?
And we find that the number of turns in a solenoid is equal to its length times the magnetic field strength at its center divided by naught times the current in the solenoid .
What is the magnetic field outside the ideal solenoid?
It is well known that the longitudinal magnetic field outside an ideal solenoid (i.e., one that is wound infinitely tightly and that is infinitely long) is zero.
What will be the magnetic field outside a long current carrying solenoid?
Note: For a very long solenoid the magnetic field outside will be zero and magnetic will be present only inside the solenoid.
Is solenoid a permanent magnet?
1. A solenoid is a temporary magnet as it can readily be demagnetized by stopping the current through the solenoid whereas a bar magnet which is a permanent magnet cannot be demagnetized.